2x^2+45x+25=0

Solution for 2x^2+45x+25=0 equation:

2x^2+45x+25=0

a = 2; b = 45; c = +25;
Δ = b2-4ac
Δ = 452-4·2·25
Δ = 1825
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1825}=\sqrt{25*73}=\sqrt{25}*\sqrt{73}=5\sqrt{73}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-5\sqrt{73}}{2*2}=\frac{-45-5\sqrt{73}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+5\sqrt{73}}{2*2}=\frac{-45+5\sqrt{73}}{4}
$